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I am studying for exam so if any persons from maths or computer science background pls help. In this question they are asking to find which function has a larger growth rate. There are two functions f(n) and g(n)

If f(n) = o(g(n)) then limit n tending to infinity (f(n))/(g(n)) = 0

Simply put, for very large positive values of n tending to infinity which function will give larger value? f(n) or g(n)?

f(n) = n^(log n)

g(n) = 2^[sqrt(n)]

>IMPORTANT: Here log n means to log with base 2

This sir is saying that g(n) = o(f(n)) and he has claimed so using the following logic. If you take log base 2 on both f(n) and g(n) you get:

log(log(f(n))) = 2 * log(log n)

log(log(g(n))) = (0.5 * (log n)) + log(log 2)

Now log(log(f(n))) = O(log(log(n)))

and log(log(g(n))) = O(log n)

Post too long. Click here to view the full text.

2 posts omitted. Click reply to view.If f(n) = o(g(n)) then limit n tending to infinity (f(n))/(g(n)) = 0

Simply put, for very large positive values of n tending to infinity which function will give larger value? f(n) or g(n)?

f(n) = n^(log n)

g(n) = 2^[sqrt(n)]

>IMPORTANT: Here log n means to log with base 2

This sir is saying that g(n) = o(f(n)) and he has claimed so using the following logic. If you take log base 2 on both f(n) and g(n) you get:

log(log(f(n))) = 2 * log(log n)

log(log(g(n))) = (0.5 * (log n)) + log(log 2)

Now log(log(f(n))) = O(log(log(n)))

and log(log(g(n))) = O(log n)

Post too long. Click here to view the full text.

>Comparing logarithms instead of functions

Nigger you can't do that

Nigger you can't do that

File: 1653155529804.gif (123.32 KB, 334x281, anime-girl.gif) ImgOps Google iqdb

>>566178

Okay so what is proper method if I have increasing functions returning positive values that are difficult to find O function for just by looking

Okay so what is proper method if I have increasing functions returning positive values that are difficult to find O function for just by looking

>>566179

Actually disregard that you may just take logarithms

That ln f(y) > ln g(y) is not a necessary but nevertheless a sufficient condition

Thing is

>log(f(n)) = (log n)^2

>log(g(n)) = sqrt(n) * log 2

>Intuitively I know that log(g(n)) = o(log(f(n)))

is plain wrong

You may apply l'hopital's rule and see why

Actually disregard that you may just take logarithms

That ln f(y) > ln g(y) is not a necessary but nevertheless a sufficient condition

Thing is

>log(f(n)) = (log n)^2

>log(g(n)) = sqrt(n) * log 2

>Intuitively I know that log(g(n)) = o(log(f(n)))

is plain wrong

You may apply l'hopital's rule and see why

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File: 1653159622317.webm (2.84 MB, 636x360, hitler car.webm) ImgOps Google iqdb

edgemaster, thoughts on *Anthony Albanese* becoming the next prime minister of australia?

2 posts omitted. Click reply to view.the anglo saxon countries n usa allies are racially done theory

>>566192

you should have voted alt left

you should have voted alt left

which country is illyria in imperator rome

M2004J19PI · Instagram · Bacoor, Philippines

**Fortune**

A journey of a thousand miles begins with a cash advance.

(YOLO)

A journey of a thousand miles begins with a cash advance.

(YOLO)

File: 1653136532557.gif (4.96 MB, 480x270, 1ycmcrw35p091.gif) ImgOps Google iqdb

File: 1653137658839.mp4 (168.62 KB, 480x270, 1ycmcrw35p091.mp4) ImgOps Google iqdb

>>566110

why 5 mb gif instead of 170kb webm

why 5 mb gif instead of 170kb webm

>>566114

to troll the poorfag india anons with mobile internet

to troll the poorfag india anons with mobile internet

Dead niggers. Executed niggers. Croaked niggers. Niggers being killed. I love dead niggers. Kill all niggers. Make a nigger cry. Bash a nigger skull in. We make a nigger dead.

5 posts omitted. Click reply to view.>>566149

what word would you use to explain racistness

what word would you use to explain racistness

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